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Jerry measured and timed the descent of a diving bell spider in a large fish tank. The spider reached a position 412 412 inches below the surface of the water after descending at a constant rate for 112 112 seconds. Jerry recorded this as −412 −412 inches. What is the position of the spider relative to the surface after 1 second? Enter your answer in the box.

Verified Answer :

calculista

Step 1

Convert mixed numbers to an improper fractions

\(4\frac{1}{2} =\frac{4*2+1}{2}= \frac{9}{2}\)

\(1\frac{1}{2} =\frac{1*2+1}{2}= \frac{3}{2}\)

Step 2

Find the unit rate of the descending

\(unit\ rate= \frac{(9/2)}{(3/2)}=3 \frac{inches}{sec}\)

therefore

the answer is

the position of the spider relative to the surface after \(1\) second is \(-3\ inches\)


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