Each croquet ball in a set has a mass of 0.50 kg. the green ball travels at 10.5 m/s and strikes a stationary red ball. if the green ball stops moving, what is the final speed of the red ball after the collision?
Momentum conservation law!
mv before collision = mv after collision
momentum of green ball before collision 0.5 kg 10.5 m/s + momentum of red ball before collision 0.5 kg 0 m/s = momentum of green ball after collision 0.5 kg 0 m/s + momentum of red ball before collision 0.5 kg unknown speed in m/s
0.510.5 + 0.50 = 0.50 + 0.5v
v = 10.5 m/s
Explanation:
It is given that,
Mass of both green and red ball, m₁ = m₂ = 0.5 kg
Initial speed of green ball, u₁ = 10.5 m/s
Initial speed of red ball, u₂ = 0 ( rest )
Final speed of green ball, v₁ = 0 (it stops)
We need to find the final speed of the red ball after the collision. Lt it is equal to v₂. Using the conservation of momentum as :
\(m_1u_1+m_2u_2=m_1v_1+m_2v_2\)
\(m_1u_1+0=0+m_2v_2\)
\(v_2=\dfrac{m_1u_1}{m_2}\)
Since, m₁ = m₂
\(v_2=u_1\)
So, the final speed of red ball after the collision is 10.5 m/s. Hence, this is the required solution.