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isyllus

Answer:

The factor of \(-4+8a-4a^2\) is \(-4(a-1)^2\)

A is correct.

Step-by-step explanation:

Given: \(-4+8a-4a^2\)

We need to factor the trinomial.

First we will take common factor from each term.

\(\Rightarrow -4\cdot 1-4\cdot -2a-4\cdot a^2\)

Take out -4 common

\(\Rightarrow -4(1-2a+a^2)\)

Using formula of perfect square.

\(x^2-2xy+y^2=(x-y)^2\)

\(\Rightarrow -4(a-1)^2\)

Hence, The factor of \(-4+8a-4a^2\) is \(-4(a-1)^2\)

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