If you stand on a bathroom scale,the spring inside the scale compresses 0.50 mm, and it tells you your weight is 700 N. Now if you jump on the scale from a height of 1.3 m, what does the scale read at its peak?
Initially, mg = kx. K = mg/x = 700/0.5x10^-3 = 1400000N/m. From second condition, applying work-energy theorem, potential enery- elastic potential energy = change in kinetic energy. Now change in kinetic energy is 0 since initial and final velocities are 0m/s. Therefore, potential energy = elastic potential energy. mgh = (1/2) k x^2. x^2 = 2(mg)h/k = 2 x 700 x 1.3/ 1400000. x = 0.036m. Hope it's clear.
The scale reading at its peak is 0.036m.
If an object is lifted, work is done against gravitational force. The object gains energy.
If you stand on a bathroom scale, the spring inside the scale compresses 0.50 mm, and it tells you your weight is 700 N.
Using Hooke's law, expressed as
Force, F = k (x₂-x₁).
mg = kx.
k= mg/x
Put the values, we get
k = 700/0.5x10^-3
k = 1400000 N/m.
Now if you jump on the scale from a height of 1.3 m,
Applying work-energy theorem,
potential energy = elastic potential energy
mgh = (1/2) kx²
x = 2(mg)h/k
Plug the values, we get
x = 2 x 700 x 1.3/ 1400000
x = 0.036m.
Thus, the scale reading at its peak is 0.036m.
Learn more about gravitational potential energy.
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