Answer:
The perimeter of Square B is (-24x+100) units much bigger than Square A.
Step-by-step explanation:
Side length of square A = (2x-7)
Side length of square B = (-4x+18)
Perimeter of a square is
\(Perimeter=4a\)
where, a is side length of square.
Perimeter of square A is
\(Perimeter=4(2x-7)=4(2x)+4(-7)=8x-28\)
Perimeter of square B is
\(Perimeter=4(-4x+18)=4(-4x)+4(18)=-16x+72\)
Difference between perimeter of Square B than Square A is
\(Difference=-16x+72-(8x-28)\)
\(Difference=-16x+72-8x+28\)
Combined like terms.
\(Difference=(-16x-8x)+(72+28)\)
\(Difference=-24x+100\)
Therefore, the perimeter of Square B is (-24x+100) units much bigger than Square A.
