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A closed container has 2.04 ⋅ 1023 atoms of a gas. Each atom of the gas weighs 1.67 ⋅ 10−24 grams. Which of the following shows and explains the approximate total mass, in grams, of all the atoms of the gas in the container?

A0.34 grams, because (2.04 ⋅ 1.67) ⋅ (1023 ⋅ 10−24) = 3.4068 ⋅ 10−1
B0.37 grams, because (2.04 + 1.67) ⋅ (1023 ⋅ 10−24) = 3.71 ⋅ 10−1
C3.41 grams, because (2.04 ⋅ 1.67) ⋅ (1023 ⋅ 10−24) = 3.4068
D3.71 grams, because (2.04 + 1.67) ⋅ (1023 ⋅ 10−24) = 3.71

Verified Answer :

2.04 ⋅ 10^23 * 1.67 ⋅ 10^−24 = 
0.34 grams, because (2.04 ⋅ 1.67) ⋅ (1023 ⋅ 10−24) = 3.4068 ⋅ 10−1

JeanaShupp

Answer:-a) 0.34 grams, because \((2.04\cdot1.67)\cdot(10^{23}\cdot10^{-24})=3.4068\cdot10^{-1}\ grams.\)


Explanation:-

Given:

Number of atoms in a closed container \(=2.04\times10^{23}\)

Weight of one atom\(=1.67\times10^{-24}\)

Total mass of all the atoms of the gas in the container\(=\text{Number of atoms}\times\text{Weight of one atom}\)

\(=2.04\times10^{23}\times1.67\times10^{-24}\)

\((2.04\times1.67)(\times10^{23-24})\)

\(=3.40\times10^{-1}=0.34068\ grams\)

Thus A is the right option.