Answer : The correct option is, (B) \(\frac{3}{2}\)
Step-by-step explanation:
The formula used for slope is:
\(m=\frac{(y_2-y_1)}{(x_2-x_1)}\)
where,
m = slope
\(x_1\) and \(x_2\) are the coordinates of x-axis
\(y_1\) and \(y_2\) are the coordinates of y-axis
From the graph we conclude that:
\(x_1\) and \(x_2\) are (-2) and (2) respectively.
\(y_1\) and \(y_2\) are (-4) and (2) respectively.
Now put all the given values in the above formula of slope, we get:
\(m=\frac{(y_2-y_1)}{(x_2-x_1)}\)
\(m=\frac{(2-(-4))}{(2-(-2))}\)
\(m=\frac{(2+4)}{(2+2)}\)
\(m=\frac{6}{4}\)
\(m=\frac{3}{2}\)
Therefore, the slope of line segment EF is, \(\frac{3}{2}\)
