Answer:
\(14.7\ in^{3}\)
Step-by-step explanation:
Step 1
Find the volume of Cup A
we know that
The volume of a cone is equal to
\(V=\frac{1}{3}\pi r^{2} h\)
where
r is the radius of the base of the cone
h is the height of the cone
In this problem we have
\(r=2/2=1\ in, h=4\ in\)
substitute
\(V=\frac{1}{3}\pi (1)^{2} (4)\)
\(Va=\frac{4\pi}{3}\ in^{3}\)
Step 2
Find the volume of Cup B
we know that
The volume of a cylinder is equal to
\(V=\pi r^{2} h\)
where
r is the radius of the base of the cylinder
h is the height of the cylinder
In this problem we have
\(r=2/2=1\ in, h=6\ in\)
substitute
\(V=\pi (1)^{2} (6)\)
\(Vb=6\pi\ in^{3}\)
Step 3
Find the difference of volume
\(Vb-Va=6\pi\ in^{3}-\frac{4\pi}{3}\ in^{3}\\\\=\frac{14\pi}{3}\\\\=14.7\ in^{3}\)
