Description of motion.
1) From the stop sign until a unknowm moment: acceleration from 0 m/s to 60 m/s, during x seconds
You do not know the time during which the driver kept this motion.
2) During 20 s (after having finished of accelerating), constant speed = 60 km/h, from x s until x + 20s
3) From x+20 s to 40 s, c onstant acceleration from 60 km/h to 0 km/h
With the information you cannot tell, in what stage was the driver at t = 35 s, because you need to know x.
Sure that information is in a graph or other part of the question which was not included in your question.
I will tell you how to calculate the acceleration in any of the three stages, once you have x.
1) First stage:
If the motion is uniformly accelerated, Vf = Vo + at => a = [Vf - Vo] / t
Vf = 60 km/h (which you must pass to m/s)
Vo = 0 (from rest because she started from a stop sign)
t = x seconds
=> a = [60km/h (1000m/km)(1h/3600s)] / x = (16.67 m/s) / x s
2) Second stage: constant speed.
Consequently, acceleration = 0
3) Third and last stage: uniform acceleration during 40 - (x+20) s
Once you know x, you will know the time during which she was braking.
Vf = Vo + at => a = [Vf - Vo] / t =
a = [0 - 60km/h] [1h / 3600s] [ 1000m / 1km] / [40s - (x+20)s]
a = - [601000/3600 m/s] / [20s - xs] =
The negative sign means that the acceleration is opposed to the velocity (braking).
