The answer is A) 2.50 moles
Atomic masses (A) of the following atoms are:
A(C) = 12 g/mol
A(O) = 16 g/mol
A(H) = 1 g/mol
A(S) = 32 g/mol
The number of moles (n) is the quotient of mass (m) and molar mass (M)
n = m/M
m(CH4) = 16.0 g
M(CH4) = A(C) + 4A(H)= 12 + 4 1 = 12 + 4 = 16 g/mol
n(CH4) = 16.0 g / 16 g/mol = 1 mol
m(O2) = 16.0 g
M(O2) = 2A(O) = 2 16 = 32 g/mol
n(O2) = 16.0 g / 32 g/mol = 0.5 mol
m(SO2) = 16.0 g
M(SO2) = A(S) + 2A(O)= 32 + 2 16 = 32 + 32 = 64 g/mol
n(SO2) = 16.0 g / 64 g/mol = 0.25 mol
m(CO2) = 33.0 g
M(CO2) = A(C) + 2A(O)= 12+ 2 16 = 12 + 32 = 44 g/mol
n(CO2) = 33.0 g / 44 g/mol = 0.75 mol
The total number of moles of gas in the sample is:
n(CH4) + n(O2) + n(SO2) + n(CO2) = 1 mol + 0.5 mol + 0.25 mol + 0.75 mol =
= 2.50 moles
