Can someone (preferably one of the long-term tutors) check my answers:
Researchers trap 23 devils, and find that 18 of them are infected. Provide an estimate of disease prevalence.
p-hat = (18/23)=0.783 Part II: assuming the same disease prevalence from above.
If they trap 2 devils, what’s the probability that they will get an appropriate pair (i.e. one uninfected female and one uninfected male)?
I used Combinatorics: 23 total, 18 infected and 5 uninfected Prevalence: 0.783 5C2/23C2 = 10/253 = 0.0395 (0.0395)(.783) = .0309 or 3.1% Just need to make sure I'm on the right track. Thanks for your help.
Researchers trap 23 devils, and find that 18 of them are infected. Provide an estimate of disease prevalence.
p-hat = (18/23)=0.783 Part II: assuming the same disease prevalence from above.
If they trap 2 devils, what’s the probability that they will get an appropriate pair (i.e. one uninfected female and one uninfected male)?
I used Combinatorics: 23 total, 18 infected and 5 uninfected Prevalence: 0.783 5C2/23C2 = 10/253 = 0.0395 (0.0395)(.783) = .0309 or 3.1% Just need to make sure I'm on the right track. Thanks for your help.
