Find the area of the surface of revolution generated by revolving the curve y = 3 sqrt (x), 0 <= x <= 4, about the x-axis.
Okay, so I've set up the integral like this: 2pi ∫[0,4] (3 sqrt (x))(sqrt(1+(1/4x)))dx Which is coming out to 108.5, but that's not giving me the right answer. Can you help me set up the integral correctly or tell me what I'm doing wrong?
Okay, so I've set up the integral like this: 2pi ∫[0,4] (3 sqrt (x))(sqrt(1+(1/4x)))dx Which is coming out to 108.5, but that's not giving me the right answer. Can you help me set up the integral correctly or tell me what I'm doing wrong?