A geometry student wants to draw a rectangle inscribed in a semicircle of radius of 8. If one side must be on the semicircle's diameter, what is the area of the largest rectangle that the student can draw?
for the answer to the question above, let's start with the whole circle.
Let's assume that the maximum possible area of a rectangle inscribed in a complete circle is achieved when the rectangle is a square.
D= Circle's Diameter = 16
square's area = (D^2) / 2 = 256/2 =128
Imagine we want to break the circle into two semicircles, the square would be divided into two rectangles which would have the maximum possible area.
rectangle's area = square's area / 2 = 128/2 = 64
For the solution of the Geometry above, let's begin with the complete circle. Let's assume that the most viable location of a rectangle inscribed in a whole circle is completed whilst the rectangle is rectangular.
D = circle's diameter = 16
Square area = (D*2)/2 = 256/2 = 128.
Imagine we need to interrupt the circle into semi-circles. The rectangular could be divided into rectangles, which could have the most viable location.
Rectangle area = square area divided by two
= 128/2
= 64.
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