Hello!
First, let's write the problem.
\(3x+\frac{1}{5}y=7\)
Subtract 3x from both sides.
\(3x+\frac{1}{5}y-3x=7-3x\)
\(\frac{1}{5}y=7-3x\)
The opposite of division is multiplication, so we are going to multiply in order to undo the fraction.
\(5\cdot \frac{1}{5}y=5\cdot \:7-5\cdot \:3x\)
Our final answer would be,
\(y=35-15x\)
Thanks!
-TetraFish