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wizard123

The first function \(3x^2 +y^2 = 4\) describes an ellipse.
The 2nd function \(x^2 +y =5\) describes a parabola.

If you draw an ellipse and then draw a parabola where vertex is centered and above ellipse, you will see that it intercepts the ellipse twice on either side.

Maximum number of solutions = 4

calculista

Answer:

The system has no solution

Step-by-step explanation:

we have

\(3x^{2} +y^{2}=4\) ------> equation A

\(x^{2} +y=5\) -----> equation B

we know that

The solution of the system of equations is the intersection points both graphs

Using a graphing tool

see the attached figure

The figure has no point of intersection

therefore

The system has no solutions

View image calculista

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