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A 1,500.0 kg car hits a brick wall with a force of 60.0 N in 1.75 seconds. What is the change in the momentum of the car?

Verified Answer :

FR1X

Momentum Formula
p=m x v
p= kg x m/s

1N= 1kg x m/s^2
 In this case we don't have the "v" variable, speed.
So, we multiply:
=60N x 1.75s
=60 kg x m/s^2 x 1.75s
=105 kg x m/s

skyluke89

105 kg m/s

Explanation:

The change in momentum of the car is equal to the impulse, which is equal to the product between the force applied and the time of the collision:

\(\Delta p= F \Delta t\)

in this case, the force applied is F=60.0 N, while the time of the collision is \(\Delta t=1.75 s\), so the change in momentum of the car is

\(\Delta p=(60.0 N)(1.75 s)=105 kg m/s\)

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