How many molecules are contained in 55.0 g of H2SO4
moles of H2SO4 = 55/98 = 0.56mol. Number of molecules of H2SO4 = moles x 6.02 x 10^23 = 0.56 x 6.02 x 10^23 = 3.37 x 10^23. Hope it helps
Answer: \(3.37\times 10^{23}\) molecules of \(H_2SO_4\)
Explanation: To calculate the moles, we use the formula:
\(Moles=\frac{\text{Given mass}}{\text{Molar mass}}\)
Given mass= 55.0 g
Molar mass= 98g/mol
\(Moles=\frac{55.0g}{98g/mol}=0.56moles\)
1 mole of \(H_2SO_4\) contains =\(6.023\times 10^{23}\) molecules of \(H_2SO_4\)
0.56 moles of \(H_2SO_4\) contains =\(\frac{6.023\times 10^{23}}{1}\times 0.56=3.37\times 10^{23}\) molecules of \(H_2SO_4\)