Answer:
Positive Difference = 100 grams
Step-by-step explanation:
We have two compound A and B
Compound A: \(y=500(0.5)^x\)
We have to find initial value of compound A. For initial value, we will put x=0 into equation.
Initial amount \(=500(0.5)^0\)
Initial amount of compound A = 500 grams
Compound B:
Time (h) : 1 2 3
Compound B : 200 100 50
First we have to make the function for compound B.
According to table we can see amount becomes 50% of previous value every hour.
In 1 hour, Compound B = 200 grams
Initial amount should be 50% more than 200.
Initial amount of Compound B = 400 grams
We need to find positive difference of initial amount of compound A and B
Difference = 500 - 400
Positive Difference = 100 grams
Hence, The positive difference of initial amount of Compound A and Compound B is 100 grams.
