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  1. A sample of table sugar (sucrose, C12H22O11) has a mass of 1.202 g.

ACalculate the number of moles of C12H22O11 contained in the sample and record in Table 1. Show your work.

BCalculate the moles of each element in C12H22O11 and record in Table
  1. Show your work.

CCalculate the number of atoms of each type in C12H22O11 and record in

Table 1. Show your work.

Verified Answer :

MissPhiladelphia

a. Calculate the number of moles of C12H22O11 contained in the sample and record
 1.202 g C12H22O11 ( 1 mol / 342.30 g ) = 0.0035 mol C12H22O11

b. Calculate the moles of each element in C12H22O11

0.0035 C12H22O11 ( 12 mol C / 1 mol C12H22O11 ) = 0.042 mol C
0.0035 C12H22O11 ( 22 mol H / 1 mol C12H22O11 ) = 0.077 mol H
0.0035 C12H22O11 ( 11 mol C / 1 mol C12H22O11 ) = 0.0385 mol O

c. Calculate the number of atoms of each type in C12H22O11

0.042 mol C ( 6.022x10^23 atoms / 1 mol ) = 2.53x10^22 atoms C
0.077 mol H ( 6.022x10^23 atoms  / 1 mol  ) = 4.64x10^22 atoms H
0.0385 mol O ( 6.022x10^23 atoms  / 1 mol  ) = 2.32x10^22 atoms O

Explanation:

Given mass of sugar = 1.202 g

Molar mass of the sugar , \(C_{12}H_{22}O_{11}\) = 342.29 g/mol

a) Number of moles of sugar

\(\text{number of moles}=\frac{\text{given mass of sugar}}{\text{molar mass of sugar}}=\frac{1.202 g}{342.29g/mol}=0.0035 mol\)

Number of moles of sugar in 1.202 grams is 0.0035 moles

b)Moles of each element in \(C_{12}H_{22}O_{11}\)

In a molecular formula of sugar there are 12 carbon, 22 hydrogen and 11 oxygen atoms

Moles of an element in molecule =

number of atoms of that element in a molecular formula × number of moles of compound

Moles of carbon = 12 × 0.0035 = 0.042 moles

Similarly

Moles of hydrogen = 22  × 0.0035 = 0.077 moles

Moles of oxygen =11 × 0.0035 = 0.0385 moles

c) Number of atoms of each type in \(C_{12}H_{22}O_{11}\)

\(\text{Number of atoms}=\text{number of moles of that atom in a molecular formula}\times \text{Avogadro number}\)

Number of carbon atoms =\(0.042 mole\times 6.022 \times 10^{23}=2.52\times 10^{22} atoms\)

Number of hydrogen =\(0.077mole\times 6.022 \times 10^{23}=4.63\times 10^{22} atoms\)

Number of oxygen atoms = \(0.0385 mole\times 6.022 \times 10^{23}=2.31\times 10^{22} atoms\)