How do i calculate:((6 x y−2 x y)−x2y2)+10 x y
6xy−2xy−x2y2+10xy=6xy+−2xy+−x2y2+10xy=6xy+−2xy+−x2y2+10xy=(−x2y2)+(6xy+−2xy+10xy)=−x2y2+14xy=−x2y2+14xy
4xy-x2y2=-10xy-x2y2=-14xyx2y2=14xynd classi think its the answer it can be solved after but it will only get complicated ....it depends on yor chapter a
