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Two 1.60cm×1.60cm plates that form a parallel-plate capacitor are charged to ± 0.711nC . What is the potential difference across the capacitor if the spacing between the plates is 1.20mm What is the potential difference across the capacitor if the spacing between the plates is 2.40mm ?

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HomertheGenius

The surface charge density:
S(igma) = Q / A
A = 1.6 10^(-2) 1.6 10^(-2) = 2.56 10^(-4) m²
The electric field:  E = S / E(psilon) o 
E = 0.711 10^^(-9) / ( 2.56 10 ^(-4) 8.85 10 ^(-12) ) = 
= 0.3138 10 ^6 = 3.138 10^5 V/m
a ) Δ V = E d
Δ V = 3.138 10^5 V/m 1.2 10^(-3) m = 376.56 V
b ) When d = 2.40 mm:
Δ V = 3.138 10^5 V/m 2.40 10^(-3) m = 753.12 V

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