The length of a rectangle is three times its width. If the perimeter is at most 112 centimeters, what is the greatest possible value for the width? Write an inequality to model the problem.

A2w + 2 • (3w) ≥112
B2w + 2 • (3w) < 112
C2w + 2 • (3w) > 112
D2w + 2 • (3w) ≤112

Question 2.2. The length of a rectangle is five times its width. If the perimeter is at most 96 centimeters, what is the greatest possible value for the width?

A40 cm
B19.2 cm
C16 cm
D8 cm

Q2. The answer is D. 2w + 2 • (3w) ≤112

The perimeter of a rectangle is: P = 2w + 2l (w - weight, l - length)

The perimeter is at most 112 centimeters: P ≤ 112
The length of a rectangle is three times its width: l = 3w

P ≤ 112
2w + 2l ≤ 112

l = 3w
2w + 2 (3w) ≤ 112

Q2.2. The answer is D. 8 cm

The perimeter of a rectangle is: P = 2w + 2l (w - weight, l - length)

The length of a rectangle is five times its width: l = 5w
The perimeter is at most 96 centimeters: P ≤ 96

P ≤ 96
2w + 2l ≤ 96

l = 5w
2w + 2 5w ≤ 96
2w + 10w ≤ 96
12w ≤ 96
w ≤ 96 : 12
w ≤ 8 cm