In training for a triathlon, Yuna swam 1.9 miles in the open ocean, which took her 2 hours. For the first part of her swim, she averaged 1.4 miles per hour. For the second part of her swim, she swam against the current and started to tire, so her average speed decreased to 0.8 mph. What was the distance of the first part of Yuna's swim? Round to the nearest tenth as needed. The distance in the first part of her swim was miles.
we know that
Yuna swam \(1.9\)miles in the open ocean in \(2\) hours
so the average rate is equal to
\(\frac{1.9}{2}=0.95\frac{miles}{hour}\)
Let
x------> the distance in miles of the first part
y-----> the time in hours of the first part
we know that
First Part
\(1.4=\frac{x}{y}\) -------> equation A
Second Part
\(0.8=\frac{1.9-x}{2-y}\) -------> equation B
Using a graphing tool -----> to solve the system equations
see the attached figure
The solution is the point \((0.7,0.5)\)
that means
\(x=0.7\ miles\\y=0.5\ hours\)
therefore
the answer is
The distance in the first part was \(0.7\ miles\)
Answer:
the answer is 0.7
Step-by-step explanation:
i got it right on edge