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Verified Answer :

\(x-y=3\)
\(x+2y=-6\)

Subtract both equations to isolate and solve for y.

\((x-x)+(-y-2y)=3-(-6)\)
\(0+-3y=9\)
\(y=-3\)

Now, solve for x in either equation by plugging in the y value.
I will choose the simpler first equation: \(x-y=3\)

\(x+3=3\)
\(x=0 ; y=-3\)

x - y = 3 >> x = 3 + y
substituting this x in the second equation gives us
3 + y + 2y = -6 >> 3y = -9 >> y = -3
substituting this value of y in x = 3 + y gives us:
x = 3 + (-3) = 3 - 3 = 0

so the solution is: y = -3 and x = 0

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