1davey29 1davey29

13-12-2016
Mathematics

Answered

Let f(x)=cos(arctanx). What is the range of f?

A{x|-(pi/2)
A{x|0
A{x|0=
A{x|-1
A{x|-1=

Verified Answer :

13-12-2016

-π/2 < arctan(x) < π/2

So cos(π/2) < cos(arctan(x)) < cos(0)

0 < cos(arctan(x)) < 1

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