Answer : Option A) [Xe] \(6s^{2}4f^{14}5d^{10}6p^{2}\)
Explanation : Lead is the element which is represented in the ground state electron configuration as [Xe] \(6s^{2}4f^{14}5d^{10}6p^{2}\).
It has only 2 + 14 + 10 + 2 = 28 electrons and protons more than that of Xenon.
Xenon has atomic number as 54, now adding 28 protons in its atom will make it 82 which the atomic number of Lead.
