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x=11-y




4. (11-y)^2-3y^2=8

calculista

we have

\(x+y=11\)

\(x=11-y\) --------> equation A

\(4x^{2} -3y^{2}=8\) ----> equation B

Substitute equation A in equation B

\(4(11-y)^{2} -3y^{2}=8\)

therefore

the answer is the option B

\(4(11-y)^{2} -3y^{2}=8\)

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