Here, I've attached a picture of the triangle that accompanies this explanation.
cot = \(\frac{1}{tan}\) = \(\frac{1}{ \frac{sin}{cos} }\) = \(\frac{cos}{sin}\)
Now view the triangle.
PS. Angle theta will have a coordinate of (-, +) because it is in quadrant II.
sin of the angle would be opposite/hypotenuse, so sin = \(\frac{1}{ \sqrt{10} }\)
cos of the angle would be adjacent/hypotenuse, so cos = \(\frac{-3}{ \sqrt{10} }\)
tan of the angle would be opposite/adjacent, so tan = \(- \frac{1}{3}\)
