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In the image, point A is the center of the circle. Which two line segments must be equal in length?


AH¯¯¯¯¯ and BC¯¯¯¯¯


HI¯¯¯¯ and BC¯¯¯¯¯


EF¯¯¯¯¯ and HI¯¯¯¯


EF¯¯¯¯¯ and AI¯¯¯¯

In the image, point A is the center of the circle. Which two line segments must be equal in length? AH and BC HI and BC EF and HI EF and AI class=

Verified Answer :

Nirina7

the answer

the true answer is  
EF¯¯¯¯¯ and HI¯¯¯¯

proof

the line EF passes on A, and so does the line HI. both line are called diameter of the circle, that means
EF = HI

JeanaShupp

Answer: \(\overline{EF}=\overline{HI}\)

Step-by-step explanation:

Given: In the image, point A is the center of the circle.

Therefore every straight line segments passing from one to another point of circle through the center of circle A is the diameter of the circle.

Since, \(\overline{EF}\) and  \(\overline{HI}\) are the line segments passing from side to side of circle through the center of circle A is the diameter of the circle, then both are representing diameter of the given circle.

Since, all the diameter of a circle has a unique length .

Hence, the  line segments must be equal in length :

\(\overline{EF}=\overline{HI}\)

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