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Verified Answer :

Answer: The density of the cube of metal is \(8.91g/cm^3\)

Explanation:

To calculate the volume of cube, we use the formula:

\(V=a^3\)

where,

a = edge length of cube

Edge length of cube = 1.2 cm

Volume of cube = \((1.2)^3=1.728cm^3\)

To calculate density of a substance, we use the equation:

\(\text{Density}=\frac{\text{Mass}}{\text{Volume}}\)

We are given:

Mass of cube = 15.4 g

Volume of cube = \(1.728cm^3\)

Putting values in above equation, we get:

\(\text{Density}=\frac{15.4g}{1.728cm^3}=8.91g/cm^3\)

Hence, the density of the cube of metal is \(8.91g/cm^3\)

We have that from the Question"Determine the identity of a cube of metal that measures 1.2 cm on each side and has a mass of 15.4g." it can be said that The density of the cube is

\(\rho=8912.0kg/m^3\)

From the Question we are told

Determine the identity of a cube of metal that measures 1.2 cm on each side and has a mass of 15.4g.

Generally the equation for Density is mathematically given as

\(density=\frac{m}{v}\\\\\rho=\frac{15.4*(1/1000)}{(1.2/100)^3}\)

\(\rho=8912.0kg/m^3\)

Therefore

The density of the cube is

\(\rho=8912.0kg/m^3\)

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