The probability that the first spin lands on blue is \(\dfrac{6}{8}\) (6 blue sections of all possible 8)
The probability that the second spin lands on grey is \(\dfrac{2}{8}\) (2 gray sections of all possible 8)
So, the probability that the first spin lands on blue and the second spin lands on grey is \(\dfrac{6}{8}\cdot\dfrac{2}{8}=\dfrac{3}{4}\cdot\dfrac{1}{4}=\boxed{\dfrac{3}{16}}\)
