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The height, h, of a falling object t seconds after it is dropped from a platform 300 feet above the ground is modeled by the function h(t)=300-16t^2 Which expression could be used to determine the average rate at which the object falls during the first 3 seconds of its fall?


A.) h(3) – h(0)

B.) h(3/3)-h(0/3)

C.) h(3)/3

D.) (h(3)-h(0))/3

Verified Answer :

onyebuchinnaji

The average rate at which the object falls during the first 3 seconds of its fall is \(\frac{h(3) - h(0)}{3}\).

Model of the object's motion

The function of the object's motion is given as h(t) = 300 - 16t².

Velocity of the object after 3 seconds

The velocity at which the object falls during the first 3 seconds of its fall is calculated as follows;

\(v = \frac{dh(t)}{dt} = -32t\)

Average rate

The average rate of the motion is calculated as follows;

\(v = \frac{h(3) - h(0)}{3}\)

Learn more about average rate of motion here: https://brainly.com/question/25902294

Answer:

D

Explanation:

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