Answer: \(x<-8\)
Step-by-step explanation:
The given inequality : \(3-(2x-5)<-4(x+2)\)
To solve the inequality for x , first we open the parenthesis , we get
\(3-2x+5<-4x+(-4)2\)
\(\Rightarrow\ 3-2x+5<-4x-8\) [Note : (-)(+)=(-)]
\(\Rightarrow\ 3+5-2x<-4x-8\)
\(\Rightarrow\ 8-2x<-4x-8\)
Add 4x on both sides , we get
\(8-2x+4x<-4x-8+4x\)
\(8+2x<-8\)
Subtract 8 from both sides , we get
\(2x<-16\)
Divide both sides by 2 , we get
\(x<-8\)
Hence, the correct answer is : \(x<-8\)
