What is the axis of symmetry of the function f(x) =-(x+9)(x-21)
f(x) =-(x+9)(x-21)
Manipulating algebrically,
We get,
f(x) =-(x+9)(x-21)
= -(x^2 -21x + 9x - 189)
= -(x^2 -12x - 189)
= -x^2 + 12x + 189
Axis of symmetry = -b/2a
plugging the values,
x = -12/-2
= 6
Answer:
x = 6
Step-by-step explanation:
The given equation is \(f(x)=-(x+9)(x-21)\)
We write the equation in standard form of parabola \(f(x)=ax^2+bx+c\) using FOIL
\(f(x)=-(x+9)(x-21)\\\\f(x)=-(x^2-21x+9x-189)\\\\f(x)=-x^2+12x+189\)
Now, we know that the axis of symmetry passes through the vertex. Hence, in order to find the vertex of the parabola, we find the x coordinate of the vertex.
x coordinate of the vertex is \(-\frac{b}{2a}\)
Here, a = -1 b = 12
\(-\frac{b}{2a}\\\\=-\frac{12}{2\cdot(-1)}\\\\=-(-6)\\\\=6\)
Therefore, the axis of symmetry is x = 6