in DEF DE=17 m angle =32 Find DF nearest tenth
in DEF DE=17 m angle =32 Find DF nearest tenth
Since we are asked to find DF, and we are given an angle and the side opposite to it, we can use the sine function to find DF.
let x be the length of side DF.
sin(32)= 17/x
x= 17 / sin(32)
x= 32.08
approximately 32.1
Answer:
(A) 32.1
Step-by-step explanation:
It is given that in ΔDEF, DE=17 and m∠F=32, thus
Using the trigonometry, we have
\(sinx=\frac{Perpendicular}{Hypotenuse}=\frac{DE}{DF}\)
⇒\(sin32^{\circ}=\frac{17}{DF}\)
⇒\(DF=\frac{17}{sin32^{\circ}}\)
⇒\(DF=\frac{17}{0.529}\)
⇒\(DF=32.1\)
Therefore, the value of DF is 32.1.
Hence option A is correct.