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If ∠BAC = 17° and ∠CED = 17° are the two triangles, ΔBAC and ΔCED similar? If so, by what criterion?

Ayes, by AA similarity criterion
Byes, by SAS similarity criterion
Cyes, by SSA similarity criterion
Dno, not possible to tell.

Verified Answer :

If ∠BAC = 17° and ∠CED = 17° are the two triangles, ΔBAC and ΔCED similar? If so, by yes, by AA similarity criterion 

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Answer:

Option A is correct.

Yes, by AA similarity criterion

Step-by-step explanation:

AA(Angle-Angle) Similarity Criterion states that if two angles of one triangle are congruent to two angles of another triangle, then the triangles are similar.

In ΔBAC and ΔCED

\(\angle BAC = \angle CED = 17^{\circ}\)   [Angle]        [Given]

\(\angle C = \angle C\)     [Angle]          [Common angle]

Therefore, by AA similarity criterion;

\(\triangle BAC \sim \triangle CED\)

Therefore,  ΔBAC and ΔCED are similar by AA similarity criterion.

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