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Verified Answer :

In general, the scalar multiple of k times u, is this: 

\(k\vec u = k(ux, uy)=(Kux,Kuy)\) 

So, here's how we find \(3\vec v\) 

\(3\vec v = 3 * (2,4) = (3*2,3*4) = (6,12)\) 

The answer is (6,12).

6,12 the other person explained it already

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