Web Analytics
Answered

If the current flowing through an electric heater increases from 6 to 12 amp while the voltage remains the same, the heat produced by the heater will be

Areduced one-half.
Ctwo times the original heat.
Bunchanged.
Dfour times the original heat.

Verified Answer :

mathssydney

Q=l^2 times R times t
Where Q - heat, I -current, R - resistance and t is time

If you increase I twice (and it's squared), than Q gonna went up 4 times (2 squared).

Choose last

Explanation:

It is given that,

Current, \(I_1=6\ A\)

Heat produced, \(H_1=I_1^2Rt\)............(1)      

Where

R is the resistance

t is the time taken

So, \(H_1=36Rt\)

Current, \(I_2=12\ A\)

Heat produced, \(H_1=I_2^2Rt\)      

So, \(H_2=144Rt\).............(2)

From equation (1) and (2), it is clear that

\(H_2=4\times H_1\)

So, If the current flowing through an electric heater increases from 6 to 12 amp while the voltage remains the same, the heat produced by the heater will be four times the original heat.

Related Questions