Answer:
298.716 g of \(SiH_{4}\)
Explanation:
\(SiH_{4}\) is a molecule with one atom of Si and four atoms of H.
First you should calculate the molar mass of each atom:
Molar mass of Si = 28.0855
Molar mass of H = 1.00784
So, the molar mass of the \(SiH_{4}\) will be:
Molar mass of \(SiH_{4}\) = 28.0855 + (1.00784 x 4)
Molar mass of \(SiH_{4}\) = \(32.12\frac{g}{mol}\)
it means that one mol of \(SiH_{4}\) has a molar mass of \(32.12\frac{g}{mol}\).
Now you can calulate the mass:
\(9.30molesSiH_{4}*\frac{32.12gSiH_{4}}{1molSiH_{4}}\) = 298.716 g of \(SiH_{4}\)
