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Object A attracts object B with a gravitational force of 10 newtons from a given distance. If the distance between the two objects is doubled, what is the changed force of attraction between them?

A2.5 newtons
B5 newtons
C20 newtons
D100 newtons

Verified Answer :

mathssydney

2.5
(Because formula has r squared, or 2 times 2 or 4)
So 10:4=2.5

carlosego

By definition, the gravitational force is given by:

\(F = G(\frac{m1m2}{r^2})\)

Where,

G: gravitational constant

m1: mass of object 1

m2: mass of object 2

r: distance between objects:

We know that the force is equal to 10N:

\(G(\frac{m1m2}{r^2}) = 10\)

If the distance is double we have:

\(F = G(\frac{m1m2}{(2r)^2}) = G(\frac{m1m2}{4r^2}) = \frac{1}{4}G(\frac{m1m2}{r^2})\)

\(\frac{1}{4}(10) = 2.5\)

Therefore, the new force is:

2.5 newtons

Answer:

the changed force of attraction between them is:

A. 2.5 newtons

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