What is the mass of 5.05×1021 platinum atoms?
Avogadro's number
represents the number of units in one mole of any substance. This has the value
of 6.022 x 10^23 units / mole. This number can be used to convert the number of
atoms or molecules into number of moles. We calculate as follows:
5.05×10^21 atoms Pt ( 1 mol / 6.022 x 10^23 atoms ) ( 195.084 g / 1 mol ) = 1.64 g Pt
Answer: 1.6 gram
Explanation:
According to avogadro's law, 1 mole of every substance occupies 22.4 L at STP and contains avogadro's number \(6.023\times 10^{23}\) of particles.
To calculate the moles, we use the equation:
\(\text{Number of moles}=\frac{\text{Given atoms}}{\text {Avogadro's Number}}\)
\(\text{Number of moles of water}=\frac{5.05\times 10^{21}}{6.023\times 10^{23}}=8.4\times 10^{-3}moles\)
1 mole of Platinum \(Pt\) weighs 195 g
\(8.4\times 10^{-3}moles\) of Platinum \(Pt\) weigh =\(\frac{195}{1}\times 8.4\times 10^{-3}=1.6g\)
Thus mass of \(5.05\times 10^{21}\) platinum atoms is 1.6 gram.