you randomly draw a marble from a bag of marbles that contains 7 blue marbles, 2 green marbles, and 1 red marble. what is the probability not draw a blue marble
Likely.... There is a 70% that a blue marble will be chosen so it's a 30% for the blue marvel not to be chosen
Answer:
0.3
Step-by-step explanation:
It is given that,
Number of blue marbles = 7
Number of green marbles = 2
Number of red marbles = 1
Total number of marbles = 7+2+1=10
We need to find the probability that we do not draw a blue marble.
\(P=\dfrac{\text{Number of non-blue marbles}}{\text{Total number of marbles}}\)
\(P=\dfrac{2+1}{10}\)
\(P=\dfrac{3}{10}\)
\(P=0.3\)
Therefore, the required probability is 0.3.