Answer with Step-by-step explanation:
Let f(x)=y
⇒ x=\(f^{-1}(y)\)
f(x)=2x+3=y
⇒ 2x+3=y
⇒ 2x=y-3
⇒ x=(y-3)/2
⇒ \(f^{-1}(y)=\dfrac{y-3}{2}\)
Replacing y by x
⇒ \(f^{-1}(x)=\dfrac{x-3}{2}\)
Hence, inverse of the function f(x)=2x+3 is:
\(f^{-1}(x)=\dfrac{x-3}{2}\)