Answer:
The absolute value of 4+7i is equal to \(\sqrt{4^{2}+7^{2}}\).
The absolute value of the 4+7i be \(\sqrt{65}\).
Step-by-step explanation:
The absolute value is given by .
|a + bi| = \(\sqrt{a^{2}+b^{2}}\)
Now find the absolute value of the 4+7i.
|4+ 7i|= \(\sqrt{4^{2}+7^{2}}\)
|4+ 7i| = \(\sqrt{16+49}\)
|4+ 7i| = \(\sqrt{65}\)
Therefore the absolute value of the 4+7i is \(\sqrt{65}\) .