Answer
One factor of the equation \(2x^{4} + 22x^{3} + 60x^{2}\) is x + 5 .
Option (d) is correct.
Reason
As the equation in the question is as follows
\(= 2x^{4} + 22x^{3} + 60x^{2}\)
simplify the above
Taking 2x² as a common part
= 2x²(x² + 11x + 30 )
= 2x² (x² + 5x + 6x + 30)
= 2x²(x(x+5) +6(x + 5))
= 2x²(x + 5)(x + 6)
Therefore the factors are 2x² , (x +5) , (x + 6) .
