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Verified Answer :

texaschic101
  1. y - y1 = m(x - x1)
    slope(m) = -1/3
    (3,6)...x1 = 3 and y1 = 6
    now we sub
    y - 6 = -1/3(x - 3) <==

    2. y - 9 = -(x + 2)
    y - 9 = -x - 2
    y = -x - 2 + 9
    y = -x + 7 <===

    3. y - y1 = m(x - x1)
        slope(m) = 0....horizontal lines have 0 slopes
        (-4,-1)...x1 = -4 and y1 = -1
      now we sub
        y - (-1) = 0(x - (-4)
        y + 1 = 0(x + 4) <===

    4. x + 3y = 6
         3y = -x + 6
         y = -1/3x + 2.....slope here is -1/3. A parallel line will have the same slope

    y = mx + b
    slope(m) = -1/3
    (5,3)...x = 5 and y = 3
    now we sub and find b, the y int
    3 = -1/3(5) + b
    3 = -5/3 + b
    3 + 5/3 = b
    9/3 + 5/3 = b
    14/3 = b
    ur equation is : y = -1/3x + 14/3

    5. Perpendicular lines have negative reciprocal slopes. For example : the slope of one line will be 3 and the slope of the other line would be -1/3.

    (-1,-4) / (3,3)
    slope = (3 - (-4) / (3 - (-1) = (3 + 4) / (3 + 1) = 7/4

    that means our other line has to have slope of -4/7, the negative reciprocal

    (-3,3)(4,-1)
    slope = (-1 - 3) / (4 - (-3) = -4/7

    so ur answer is (4,-1)




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