Answer : The concentration of each of the individual ions are, 0.6 M \(Ni^{3+}\) and 1.8 M \(Cl^-\).
Explanation : Given,
Concentration of \(NiCl_3\) solution = 0.6 M
The balanced chemical reaction will be :
\(NiCl_3\rightarrow Ni^{3+}+3Cl^-\)
From the balanced chemical reaction we conclude that, 1 mole of \(NiCl_3\) dissociates to give 1 mole of \(Ni^{3+}\) and 3 moles of \(Cl^-\).
So,
The concentration of \(Ni^{3+}\) = The concentration of \(NiCl_3\) = 0.6 M
The concentration of \(Cl^-\) = 3 × The concentration of \(NiCl_3\) = \(3\times 0.6M=1.8M\)
Therefore, the concentration of each of the individual ions are, 0.6 M \(Ni^{3+}\) and 1.8 M \(Cl^-\).
