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Verified Answer :

Answer:

the factor of polynomial \(2x^{2}+5x+3\) is \(=\left(x+1\right)\left(2x+3\right)\)

Step-by-step explanation:

We need to factor the polynomial \(2x^{2}+5x+3\)

Break the expression into groups,

\(=\left(2x^2+2x\right)+\left(3x+3\right)\)

\(\mathrm{Factor\:out\:}2x\mathrm{\:from\:}2x^2+2x\mathrm{:\quad }\)

\(\mathrm{Apply\:exponent\:rule}:\quad \:a^{b+c}=a^ba^c\)

\(x^2=xx\)

then

\(2x^2+2x=2xx+2x\)

\(\mathrm{Factor\:out\:common\:term\:}2x\)

\(=2x\left(x+1\right)\)

\(\mathrm{Factor\:out\:}3\mathrm{\:from\:}3x+3\mathrm{:\quad }3\left(x+1\right)\)

\(=2x\left(x+1\right)+3\left(x+1\right)\)

\(\mathrm{Factor\:out\:common\:term\:}x+1\)

\(=\left(x+1\right)\left(2x+3\right)\)

Hence, the factor of polynomial \(2x^{2}+5x+3\) is \(=\left(x+1\right)\left(2x+3\right)\)