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A 0.45 kg soccer ball changes its velocity by 20.0 m/s due to a force applied to it in 0.10 seconds. What force was necessary for this change in velocity?

Verified Answer :

nobrains

Know that change in momentum = impulse (Δp = Ft), momentum is massvelocity, and impulse is forcetime

Δp = Ft
\(m_}}v__{f}} - m_}}v__i}} = Ft \\ m(v__f}}-v__i}}) = Ft \\ (0.45kg)(20 m/s) = F(0.10s) \\ F = 90N\).

skyluke89

Answer:

90 N

Explanation:

The force applied to the ball is given by:

\(F=\frac{\Delta p}{\Delta t}\)

where

\(\Delta p\) is the change in momentum of the ball

\(\Delta t\) is the time taken

The change on momentum of the ball is:

\(\Delta p=m\Delta v=(0.45 kg)(20 m/s)=9 kg m/s\)

So, the force applied is

\(F=\frac{9 kg m/s}{0.10 s}=90 N\)

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