The expression is 9\(\frac{1}{3}^{2}\)+2+\(\frac{4}{7}\).
9\(\frac{1}{3}^{2}\)+2+\(\frac{4}{7}\) ---> First square \(\frac{1}{3}\) by squaring the top and bottom number.
=9*\(\frac{1}{9}\)+2+\(\frac{4}{7}\) ---> Multiply 9 and \(\frac{1}{9}\)
=1+2+\(\frac{4}{7}\) ---> Add
=3 \(\frac{4}{7}\) ---> Optional: turn into improper fraction
=\(\frac{25}{7}\)
